FRM Part I · FRM Exam Part I · Common Univariate Random Variables
Let X be uniform on [a, b] with mean 50 and variance 75. What is the value of b?
The upper bound b is 65. The mean of 50 implies a+b = 100, and the variance of 75 implies (b-a)^2 = 900, so b-a = 30. Solving gives a = 35 and b = 65.
- A60Correct
- B65
- C70
- D80
Explanation
Mean gives a+b = 100. Variance gives (b-a)^2 = 75 x 12 = 900, so b-a = 30. Then b = (100+30)/2 = 65, a = 35. Check: 30^2/12 = 75. Hence 65.
Did you get it right without looking?
One question tells you little. A timed set on Common Univariate Random Variables shows your real accuracy, how long you take and where you lose marks.
More Common Univariate Random Variables questions
- The sum of 100 independent daily losses, each with mean 2 and standard deviation 3 (USD million), is approximated by a normal distribution u…
- A daily operational loss estimate L is modeled as uniform on [0, 80] (in USD thousands). What is the probability that L lies between 25 and …
- A risk manager models the number of defaults among 10 independent loans, each with a default probability of 0.10. What are the mean and vari…
- A bank's trading desk has a one-day 99% VaR that is exceeded with probability 0.01 each day, independently. Over 5 trading days, what is the…
- A return is a mixture of two zero-mean normal distributions: with probability 0.9 the standard deviation is 1, and with probability 0.1 it i…
- A risk analyst models daily trading P&L of a desk as independent and identically distributed draws with mean USD 50,000 and standard deviati…