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FRM Part I · FRM Exam Part I · Common Univariate Random Variables

Let X be uniform on [a, b] with mean 50 and variance 75. What is the value of b?

The upper bound b is 65. The mean of 50 implies a+b = 100, and the variance of 75 implies (b-a)^2 = 900, so b-a = 30. Solving gives a = 35 and b = 65.

  1. A60Correct
  2. B65
  3. C70
  4. D80

Explanation

Mean gives a+b = 100. Variance gives (b-a)^2 = 75 x 12 = 900, so b-a = 30. Then b = (100+30)/2 = 65, a = 35. Check: 30^2/12 = 75. Hence 65.

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