CA Foundation · Quantitative Aptitude · Linear Inequalities
Meera scored 72 and 85 in two tests. She wants an average of at least 80 marks over three tests, with each test marked out of 100. What is the range of marks x she can score in the third test?
The third-test score must lie between 83 and 100, inclusive. The three tests must total at least 240 marks for an average of 80, and the first two give 157, so she needs at least 83, with 100 as the maximum possible.
- A80 ≤ x ≤ 100
- B83 ≤ x ≤ 100Correct
- C79 ≤ x ≤ 100
- D85 ≤ x ≤ 100
Explanation
Average condition: (72 + 85 + x)/3 ≥ 80, so 157 + x ≥ 240 and x ≥ 83. The maximum is 100. Option 80 wrongly treats the target itself as the needed score, ignoring that the first two total 157, which is below 160.
Did you get it right without looking?
One question tells you little. A timed set on Linear Inequalities shows your real accuracy, how long you take and where you lose marks.
More Linear Inequalities questions
- The graph of the inequality 2x + 5y ≤ 20 is drawn. Which statement about the boundary line and the solution region is correct?
- Consider the system x + y ≤ 6, x − y ≥ 2, y ≥ 0, with x and y integers. How many ordered pairs (x, y) satisfy all three conditions?
- If x > y and both x and y are positive real numbers, which of the following must be true?
- Which of the following is a strict inequality?
- Solve for real x: (x − 3)/4 − (2x + 1)/6 ≤ 1.
- A company produces toys in batches. Let x be the number of standard batches and y be the number of deluxe batches. Standard batches require …