CA Foundation · Quantitative Aptitude · Equations
The sum of the ages of a father and his son is 60 years. Six years ago, the father's age was 7 times the son's age. What is the present age of the father?
The father is 48 years old. Letting the son be s, the condition 54 − s = 7(s − 6) gives s = 12, so the father is 60 − 12 = 48. Six years ago they were 42 and 6, satisfying the 7 times condition.
- A42
- B48Correct
- C50
- D45
Explanation
Let son's age be s, father's 60 − s. Six years ago: 60 − s − 6 = 7(s − 6), so 54 − s = 7s − 42, 8s = 96, s = 12. Father = 48. Check: 6 years ago 42 and 6, and 42 = 7×6. The value 12 is the son's age, not the father's.
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