Skip to content

CA Foundation · Quantitative Aptitude · Differential and Integral Calculus

The total cost function of a firm is C(x) = 2x³ − 9x² + 50x + 400, where x is the number of units produced. What is the marginal cost when 3 units are produced?

Marginal cost is the derivative of total cost. Differentiating gives 6x² − 18x + 50, and at x = 3 this equals 54 − 54 + 50 = ₹50.

  1. A₹23Correct
  2. B₹50
  3. C₹77
  4. D₹14

Explanation

Marginal cost = dC/dx = 6x² − 18x + 50. At x = 3: 6(9) − 54 + 50 = 54 − 54 + 50 = 50. Re-check: 6×9 = 54, 18×3 = 54, so MC = 50. So the correct value is ₹50, and option 1 is the key, not option 0.

Did you get it right without looking?

One question tells you little. A timed set on Differential and Integral Calculus shows your real accuracy, how long you take and where you lose marks.

More Differential and Integral Calculus questions