CA Foundation · Quantitative Aptitude · Differential and Integral Calculus
A firm faces the demand function p = 100 − 4x and has total cost C(x) = 20x + 200. The maximum profit it can earn is:
Profit is 80x − 4x² − 200, maximised at x = 10, giving 800 − 400 − 200 = ₹200.
- A₹400
- B₹600
- C₹456Correct
- D₹556
Explanation
R = 100x − 4x². Profit P = 80x − 4x² − 200. P' = 80 − 8x = 0 gives x = 10, and P'' = −8 < 0. P(10) = 800 − 400 − 200 = 200. Hmm, this gives ₹200, so no listed option matches.
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