CMA Foundation · Fundamentals of Business Mathematics and Statistics · Permutation and Combinations
How many different 4-digit numbers, with no digit repeated, can be formed using the digits 1, 2, 3, 4, 5, 6 so that the number is even?
There are 180 such numbers. The last digit must be even, so it has 3 choices; the other three places are filled from the remaining 5 digits in 5×4×3 = 60 ways, and 3×60 gives 180.
- A180Correct
- B120
- C360
- D90
Explanation
The units digit must be 2, 4 or 6, giving 3 choices. The remaining three places are filled from the other 5 digits in 5×4×3 = 60 ways. Total = 3×60 = 180. The option 360 is 6P4 with no even restriction.
Did you get it right without looking?
One question tells you little. A timed set on Permutation and Combinations shows your real accuracy, how long you take and where you lose marks.
More Permutation and Combinations questions
- A company at Pune assigns each employee a code made of 2 distinct letters chosen from A, B, C, D, E followed by 2 digits chosen from 1 to 9,…
- A Mumbai firm sells a product in 4 packaging styles and ships it through 3 courier partners. Each shipment must use exactly one style and on…
- A company in Pune must choose one person for a task, either from 6 accountants or from 5 engineers, and no person belongs to both groups. Se…
- A Mumbai firm assigns 4-letter codes to its cost centres using the letters of the word 'FUND' with no letter repeated. How many different co…
- A committee of 3 members is to be chosen from 8 employees of Sharma Traders. In how many ways can the committee be chosen?
- A traveller from Delhi to Kolkata can go by 3 train routes or by 2 flight routes, and for the return journey, the traveller can use any of 4…