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CMA Foundation · Fundamentals of Business Mathematics and Statistics · Permutation and Combinations

If n!/(n-2)! = 56, what is the value of n?

The value of n is 8. The ratio n!/(n-2)! simplifies to n(n-1). Setting n(n-1) equal to 56 gives the product 8 × 7, so n is 8. Checking, 7 would give 42 and 9 would give 72, so neither fits.

  1. A6
  2. B7
  3. C8Correct
  4. D9

Explanation

n!/(n-2)! = n(n-1) = 56. Since 8 × 7 = 56, n = 8. Option 7 gives 42 and option 9 gives 72, so they do not satisfy the equation.

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