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CA Foundation · Quantitative Aptitude · Correlation and Regression

Ten trainee analysts are ranked by two examiners with no ties, and Spearman's rank correlation is found to be 0.6. What is the sum of squared rank differences, Σd²?

Σd² is 66. With n = 10 the denominator n(n²−1) is 990. Setting 1 − 6Σd²/990 = 0.6 gives 6Σd²/990 = 0.4, so Σd² = 66. Other values do not reproduce r = 0.6 under the formula.

  1. A40
  2. B33
  3. C66Correct
  4. D99

Explanation

0.6 = 1 − 6Σd²/(10×99), so 6Σd²/990 = 0.4. Then Σd² = 0.4×990/6 = 66. Choosing 99 comes from dividing by 4 instead of 6, which is a wrong rearrangement.

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