CMA Foundation · Fundamentals of Business Mathematics and Statistics · Permutation and Combinations
The board of Sundaram Textiles wants to form a 3-member audit sub-committee from 8 directors. In how many different ways can the sub-committee be selected?
The sub-committee can be selected in 56 ways. Since the order of members is irrelevant, the number of selections is 8C3, which equals 8×7×6 divided by 3×2×1, giving 56. The figure 336 would count arrangements, not selections.
- A24
- B56Correct
- C336
- D112
Explanation
Order does not matter, so use 8C3 = (8×7×6)/(3×2×1) = 336/6 = 56. The value 336 is 8P3, which wrongly counts different orderings of the same three directors.
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