CA Foundation · Quantitative Aptitude · Ratio and Proportion, Indices and Logarithms
The ratio of the ages of Anil and Bhavna is 4 : 5. Six years from now, the ratio of their ages will be 5 : 6. What is Bhavna's present age?
Bhavna's present age is 30 years. Taking ages as 4k and 5k, the condition (4k+6)/(5k+6) = 5/6 gives k = 6, so Bhavna is 5×6 = 30 years old and Anil is 24, and after six years they are 30 and 36.
- A20 years
- B25 years
- C30 yearsCorrect
- D24 years
Explanation
Let ages be 4k and 5k. Then (4k+6)/(5k+6) = 5/6, so 24k+36 = 25k+30, giving k = 6. Bhavna's age = 5×6 = 30 years. Check: 30 and 36 after six years give 5:6 for 30:36 as Anil 24 → 30, Bhavna 30 → 36, ratio 5:6. Choosing 25 would take k as 5, which ignores the equation.
Did you get it right without looking?
One question tells you little. A timed set on Ratio and Proportion, Indices and Logarithms shows your real accuracy, how long you take and where you lose marks.
More Ratio and Proportion, Indices and Logarithms questions
- Using change of base, log₂₅ 125 equals:
- Which of the following ratios is the largest?
- Given log₁₀ 2 = 0.3010, the number of digits in 2²⁰ is:
- A variable Y is inversely proportional to the square of variable X. When X = 2, Y = 18. What will be the value of Y when X = 3?
- The ratio of the ages of Anil and Bhavna is 5 : 3. If Anil is 12 years older than Bhavna, what is the sum of their present ages?
- If a/b = c/d, then by componendo and dividendo, which of the following is always true (assuming no denominator is zero)?