CA Foundation · Quantitative Aptitude · Ratio and Proportion, Indices and Logarithms
The ratio of the ages of Anil and Bhavna is 5 : 3. If Anil is 12 years older than Bhavna, what is the sum of their present ages?
The sum of their ages is 48 years. Writing the ages as 5k and 3k, the difference 2k equals 12, so k is 6. Anil is 30 and Bhavna is 18, which gives a total of 48 years.
- A48 yearsCorrect
- B40 years
- C60 years
- D32 years
Explanation
Let ages be 5k and 3k. Difference 2k = 12, so k = 6. Ages are 30 and 18, sum = 48. Check: 30 : 18 = 5 : 3. The option 40 results from taking the difference as 5k - 3k = 8k incorrectly dividing, while 60 comes from taking Anil's age as 12 times 5.
Did you get it right without looking?
One question tells you little. A timed set on Ratio and Proportion, Indices and Logarithms shows your real accuracy, how long you take and where you lose marks.
More Ratio and Proportion, Indices and Logarithms questions
- If a/b = c/d, then which of the following is obtained by applying componendo?
- The value of (27)^(2/3) × (16)^(−1/2) is:
- A variable Y is inversely proportional to the square of variable X. When X = 2, Y = 18. What will be the value of Y when X = 3?
- If 3^(x+2) = 243, then the value of x is:
- If a/b = c/d, then by componendo and dividendo, which of the following is always true (assuming no denominator is zero)?
- If log₁₀ x = 2.5 and log₁₀ y = 1.5, then log₁₀ (x²/√y) equals: