CMA Foundation · Fundamentals of Business Mathematics and Statistics · Permutation and Combinations
How many 3-digit numbers can be formed from the digits 0, 1, 2, 3, 4 if repetition of digits is allowed?
There are 100 such numbers. The hundreds place can use only 1, 2, 3 or 4 (4 choices), while the tens and units places can each use any of the 5 digits, so 4×5×5 = 100.
- A100Correct
- B125
- C80
- D60
Explanation
The hundreds digit cannot be 0, so it has 4 choices. The tens and units digits each have 5 choices. Total = 4 × 5 × 5 = 100. The option 125 wrongly allows 0 in the first place.
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