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CMA Intermediate · Operations Management and Strategic Management · Simulation and Line Balancing

Tasks A (40 s), B (30 s), C (20 s), D (50 s), E (10 s) are assigned using the largest candidate rule with cycle time 80 s. Precedence: A precedes B and C; B and C precede D; D precedes E. Stations are loaded in order, adding the largest-time eligible task that fits. What is the balance efficiency?

The balance efficiency is 93.75%. Station 1 takes A and B (70 s), and station 2 takes C, D and E (80 s). Two stations at an 80-second cycle give 160 seconds of capacity against 150 seconds of work, so efficiency is 150/160 which equals 93.75%.

  1. A62.5%
  2. B75.0%
  3. C93.75%Correct
  4. D100%

Explanation

Total time = 150 s. Station 1: A(40), then eligible B(30) and C(20); B fits, total 70; C(20) would make 90 >80, so stop. Station 2: C(20), then D(50) eligible, total 70; E(10) eligible, total 80. That makes 2 stations. Efficiency = 150/(2x80) = 93.75%. The 75% option wrongly assumes 2.5 stations... no basis; 62.5% assumes 3 stations.

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